上 x(1-x^2)dy/dx(2x^2-1)y=x^3 877620-X 3 x 2 x 1 dy / dx 2x 2 x y 1 when x 0

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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more Find dy/dx for the equation x^32x^2y3xy^2=38 asked in CALCULUS by andrew Scholar derivatives;

X 3 x 2 x 1 dy / dx 2x 2 x y 1 when x 0

X 3 x 2 x 1 dy / dx 2x 2 x y 1 when x 0-Solution to Differential equations question Solve differential equation\frac{dy}{dx}= (xy1)^2(xy1)^2 ⃤ Plainmath is a free database of mathematical1For each part, nd dy=dx (a) y= 3x3 2x2 p x Answer dy dx = 15 2 x3=2 3x1=2 (b) y= xe2x Answer dy dx = (2x 1)e2x (c) y= 1 2 sin( 2x) Answer dy dx = cos( 2x) (d) xy= x2 y2 Answer dy dx = 2x y x 2y (e) y= Z x 3 e t2 dt Answer dy dx = e x2 (f) y= ( 5x 2)4 Answer dy dx = 3( 5x 2) (g) y= R 2 x 3sin(t2)dt Answer 3sin(x2) (h) d dx

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Click here👆to get an answer to your question ️ If y = sin^1(2x/1 x^2) then find dy/dx Ex 53, 1 Find 𝑑𝑦/𝑑𝑥 in, 2𝑥 3𝑦 = sin⁡𝑥 Given 2𝑥3𝑦 = sin⁡𝑥 Differentiating both sides 𝑤𝑟𝑡𝑥 (𝑑 (2𝑥 3𝑦Dy dx = (x 2)(y 1) (x 3)(y 1) 2 Separating the variables leads to y 1 y 1 dy = x 2 x 3 dx 3 To evaluate the integrals Z y 1 y 1 dy = Z x 2 x 3 dx we need usubstitution on both sides On the LHS, let u = y 1 and then du = dy and y = u1 On the RHS we need another variable name, so let w = x 3 and then dw = dx and x = w 3 Substituting (01 below),

Help a stranger please This is for my homework and I'm having a hard time solving these equations Show the complete solutions and final answers please It will be a great help Thank you so much This covers Additional Topics on Equations of Order One, Coefficient Linear in Two Variables 1 (6x3y2)dx(2xy1)dy=0 2 (x2y1)dx(2xy5)dy=0Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreLinear in y dy dx − 2 x y = x3 sinx Integrating factor IF = e −2 R dx x = e 2ln x = eln x −2 = 1 x2 Multiply equation 1 x2 dy dx − 2 x3 y = xsinx ie d dx 1 x2 y = xsinx Integrate y x2 = −xcosx− Z 1·(−cosx)dxC0 Note integration by parts, R udv dx dx = uv − R vdu dx dx, u = x, dv dx = sinx ie y x2 = −xcosxsinxC i

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